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Program for bisection method in fortran code do loop
Program for bisection method in fortran code do loop












Why does it not do this for negative values as well? Here is my updated code: program bisec IMPLICIT NONE REAL(10):: a, b, m, f_xa, f_xb, f_xm, pi INTEGER:: i, n WRITE (*,*) 'LAB 5- Bisection Method' WRITE (*,*) '-' WRITE (*,*) ' ' WRITE (*,*) 'Please enter the interval :' READ (*,*) a,b pi = 3.1415926 DO i = 0, 1000 m = (a + b)/2. When evaluating for positive values however, no matter what the order of the numbers, it displays the correct solution. The problem I seem to be having with negative intervals though is that when I punch in evaluate from it will display -7 as a solution, however if I enter it as it will display -8 as the correct solution. I thought about testing end points too, the program seems to work fine for positive and negative values where one of the limits (A or B) is actually the solution. I wound up initializing m inside the do loop, so it's initial value is the result of the operations on A and B, and it updates through each iteration. You're right, I'm not sure why on earth I was test m instead of f_xm for the condition, but I've fixed that. I made some modifications last night, after I posted actually. This may cause you grief (like an infinite loop for some pairs ). I note that you don't do any preliminary testing to see that the interval actually contains a zero. Surely if you're looking for a root you want the value of the function f(m) to approach zero, not the value of m m is simply the midpoint x-value, which takes on values in your search interval. What is the value of m the first time the DO condition is tested (that is, what is its value just prior to entering the DO loop for the first time? F_xa = SIN(a) f_xb = SIN(b) f_xm = SIN(m) IF (ABS(m) 0) THEN a= m ELSE IF (f_xa*f_xm. The attempt at a solution program bisec IMPLICIT NONE REAL:: a, b, m, f_xa, f_xb, f_xm WRITE (*,*) 'Please enter the interval :' READ (*,*) a,b DO!WHILE (ABS(m) >1E-7) m = (a + b)/2.

program for bisection method in fortran code do loop program for bisection method in fortran code do loop

The intervals are input by the user, and then the do loop continues until the condition (m becomes very close to 0 or equals 0) is met. The problem statement, all variables and given/known data The purpose of this program is to calculate the approximate roots of the Sine function on given intervals. In the following table, each line/entry contains the program file name, the page number where it can be found in the textbook, and a brief description.

program for bisection method in fortran code do loop program for bisection method in fortran code do loop

Lagrange interpolation with the Aitken method (appeared in the book). This method is used to find root of an equation in a given interval that is value of ‘x’ for which f(x) = 0. What is Bisection Method? The method is also called the interval halving method, the binary search method or the dichotomy method.














Program for bisection method in fortran code do loop